Inverse Trigonometric Functions - Solving for an angle using Inverse Sine Function

Inverse Trigonometric Functions - Solving for an angle using Inverse Sine Function

SUBTITLE'S INFO:

Language: English

Type: Human

Number of phrases: 29

Number of words: 524

Number of symbols: 1924

DOWNLOAD SUBTITLES:

DOWNLOAD AUDIO AND VIDEO:

SUBTITLES:

Subtitles prepared by human
00:01
Hi! For today’s video, we’re going to solve a  situational problem from the concept of projectile   motion using Inverse Trig Function. The problem is:  If an object is directed at an angle theta (with  theta element of closed interval - 0 to pi over   2), then the range will be R is equals to v sub 0  squared over g times sine 2 theta (in feet) where   v sub 0 (in feet per second) is the initial speed  and g is equals to 32 feet per second squared is   the acceleration due to gravity. At what angle  shall the object be directed so that the range   will be 100 feet, given that the initial speed  is v sub zero is equals to 80 feet per second? The given are as follows: R is equals to 100 feet,   where R represents the range. V sub 0 is equals to 80 feet per second,  where it represents the initial speed and   g is equals to 32 feet per second squared,  which is the acceleration due to gravity.
01:13
To solve for this problem, let us  plug in the given values to the   formula provided to find the angle.  The formula is R is equals to v sub 0   squared over g times sine 2 theta; substitute  100 to R, 80 squared to v sub 0 squared,   32 to g. It will be 100 is equals to  80 squared over 32 times sine 2 theta. Multiply both sides by 32 over 80 squared.  Now let us reduce the 80 squared  on the right side of the equation,   and then reduce the numbers with the GCF 32. It would be 32 over 80 squared times 100 is   equals to sine 2 theta, cancelling  the term on the right side. For the left side of the equation multiply 32 over  80 squared with 100, or 100 over 1 in fraction.   The product will be 3 200 over 80 squared. Evaluate the power, it will be 3 200 over  
02:21
6 400. Reduce the fraction with 3 200, the product  shall be one half is equals to sine 2 theta. The final step is to swap the sides of the  equation: sine 2 theta is equals to one half.  But we are not yet done. What we have  accomplished is simply the value of sine 2 theta,   but not the angle, which is represented by theta.  To solve for the remaining problem, we  should use the inverse function of sine.  Two theta is equals to inverse sine of one half. Calculate, two theta is equals to pi over six.   Divide it by two, the answer will be theta  is equals to pi over 12 or 15 degrees.  So the answer will be: "The object shall  be directed at an angle of 15 degrees."

DOWNLOAD SUBTITLES: